To calculate the yield of 2,4-dichloronitrobenzene, we first need to determine the theoretical yield based on the stoichiometry of the reaction and then account for the 95% purity of the final product.1. Determine the molecular weight of nitrobenzene and 2,4-dichloronitrobenzene.Nitrobenzene C6H5NO2 : 1 12.01 * 6 + 1 1.01 * 5 + 1 14.01 + 2 16.00 = 123.11 g/mol2,4-Dichloronitrobenzene C6H3Cl2NO2 : 1 12.01 * 6 + 1 1.01 * 3 + 2 35.45 + 1 14.01 + 2 16.00 = 191.00 g/mol2. Calculate the moles of nitrobenzene used in the reaction.moles of nitrobenzene = mass / molecular weight = 10 g / 123.11 g/mol = 0.0812 mol3. Determine the stoichiometry of the reaction.Since chlorine gas is in excess, the reaction is assumed to go to completion. The stoichiometry of the reaction is 1:1, meaning that 1 mole of nitrobenzene reacts with chlorine gas to produce 1 mole of 2,4-dichloronitrobenzene.4. Calculate the theoretical yield of 2,4-dichloronitrobenzene.moles of 2,4-dichloronitrobenzene = moles of nitrobenzene = 0.0812 molmass of 2,4-dichloronitrobenzene = moles * molecular weight = 0.0812 mol * 191.00 g/mol = 15.49 g5. Account for the 95% purity of the final product.actual yield = theoretical yield * purity = 15.49 g * 0.95 = 14.72 gThe yield of 2,4-dichloronitrobenzene produced from the reaction is 14.72 grams.