The balanced chemical equation for the preparation of 2,4-dichloronitrobenzene from nitrobenzene and chlorine gas is:C6H5NO2 + 2 Cl2 C6H3Cl2NO2 + 2 HClTo calculate the theoretical yield of 2,4-dichloronitrobenzene, we first need to determine the number of moles of nitrobenzene. The molecular weight of nitrobenzene C6H5NO2 is approximately 123.11 g/mol. Given that we have 10 grams of nitrobenzene, we can calculate the number of moles as follows:moles of nitrobenzene = mass / molecular weightmoles of nitrobenzene = 10 g / 123.11 g/mol 0.0812 molSince the stoichiometry of the reaction is 1:1 1 mole of nitrobenzene reacts with 2 moles of Cl2 to produce 1 mole of 2,4-dichloronitrobenzene , the number of moles of 2,4-dichloronitrobenzene produced will be the same as the number of moles of nitrobenzene reacted.moles of 2,4-dichloronitrobenzene = 0.0812 molNow, we can calculate the theoretical yield of 2,4-dichloronitrobenzene. The molecular weight of 2,4-dichloronitrobenzene C6H3Cl2NO2 is approximately 192.00 g/mol.theoretical yield = moles of 2,4-dichloronitrobenzene molecular weighttheoretical yield = 0.0812 mol 192.00 g/mol 15.59 gSo, the theoretical yield of 2,4-dichloronitrobenzene is approximately 15.59 grams.