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What is the balanced chemical equation for the preparation of 2,4-dichloronitrobenzene from nitrobenzene and chlorine gas, and what is the theoretical yield of the reaction if 10 g of nitrobenzene is reacted with excess chlorine gas?

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The preparation of 2,4-dichloronitrobenzene from nitrobenzene and chlorine gas is an electrophilic aromatic substitution reaction. The balanced chemical equation for this reaction is:C6H5NO2 + 2 Cl2  C6H3Cl2NO2 + 2 HClTo calculate the theoretical yield, we need to find the molar mass of nitrobenzene and 2,4-dichloronitrobenzene and then use stoichiometry.Molar mass of nitrobenzene  C6H5NO2  =  6  12.01  +  5  1.01  +  1  14.01  +  2  16.00  = 123.11 g/molMolar mass of 2,4-dichloronitrobenzene  C6H3Cl2NO2  =  6  12.01  +  3  1.01  +  2  35.45  +  1  14.01  +  2  16.00  = 180.99 g/molNow, we can use stoichiometry to find the theoretical yield:10 g nitrobenzene   1 mol nitrobenzene / 123.11 g nitrobenzene    1 mol 2,4-dichloronitrobenzene / 1 mol nitrobenzene    180.99 g 2,4-dichloronitrobenzene / 1 mol 2,4-dichloronitrobenzene  = 14.71 g 2,4-dichloronitrobenzeneThe theoretical yield of the reaction is 14.71 g of 2,4-dichloronitrobenzene.

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