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Recent questions and answers in Chemical thermodynamics
0
votes
1
answer
32
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Here's a precise problem for the student to solve: Calculate the standard enthalpy change for the neutralization of 50 mL of 0.10 M hydrochloric acid (HCl) with 50 mL of 0.10 M sodium hydroxide (NaOH) at 25°C, given that the specific heat capacity of the solution is 4.18 J/(g °C) and the density of the solution is 1.00 g/mL.
answered
20 hours
ago
in
Chemical thermodynamics
by
EveretteSher
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430
points)
0
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1
answer
23
views
Here's a precise problem for a chemistry student:Calculate the standard enthalpy of formation of propane (C3H8) using the following information: ΔH°f CO2 = -393.5 kJ/molΔH°f H2O(l) = -285.8 kJ/molΔH°f C3H8(g) = ?
answered
20 hours
ago
in
Chemical thermodynamics
by
ChristalBeau
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510
points)
0
votes
1
answer
13
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Given the balanced chemical equation: 2NO(g) + O2(g) ⇌ 2NO2(g)At a certain temperature, the concentrations of NO, O2, and NO2 are 0.4 M, 0.1 M, and 0.3 M respectively. What is the reaction quotient (Qc) for this chemical reaction? Is the reaction at equilibrium or not? If not at equilibrium, which direction will it shift to reach equilibrium?
answered
21 hours
ago
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Chemical thermodynamics
by
MaxineDqh486
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390
points)
0
votes
1
answer
31
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Given a certain substance with a mass of 25 grams and an initial temperature of 25°C, if it absorbs 500 joules of heat energy, what is the final temperature of the substance? The heat capacity of the substance is 0.5 J/g·°C.
answered
21 hours
ago
in
Chemical thermodynamics
by
KirbyDent557
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530
points)
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votes
1
answer
26
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Find the standard enthalpy change for the reaction: 2C2H5OH(l) + 9O2(g) --> 6CO2(g) + 8H2O(l) given the following information: Standard enthalpy of formation (ΔHfº) of C2H5OH(l) = -277 kJ/mol Standard enthalpy of formation (ΔHfº) of CO2(g) = -393.5 kJ/mol Standard enthalpy of formation (ΔHfº) of H2O(l) = -285.8 kJ/mol Assume that the reaction occurs at standard conditions.
answered
21 hours
ago
in
Chemical thermodynamics
by
SharronMcWha
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470
points)
0
votes
1
answer
41
views
Find the standard enthalpy change for the formation reaction of methane gas (CH4) from its elements in their standard states, given the following standard enthalpy of formation values: ΔHf°[CH4] = -74.81 kJ/mol ΔHf°[H2] = 0 kJ/mol ΔHf°[C(graphite)] = 0 kJ/mol
answered
21 hours
ago
in
Chemical thermodynamics
by
BernieceOFla
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730
points)
0
votes
1
answer
33
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Determine the standard enthalpy of formation of nitrogen dioxide (NO2) given that the balanced equation for the combustion of one mole of NO2 is:4NO2(g) + 6H2O(l) → 4HNO3(aq) + 2NO(g)The standard enthalpies of formation for HNO3(l), H2O(l), and NO(g) are -174.1 kJ/mol, -285.8 kJ/mol, and 90.4 kJ/mol, respectively.
answered
21 hours
ago
in
Chemical thermodynamics
by
ChetChadwick
(
450
points)
0
votes
1
answer
26
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Determine the standard enthalpy of formation of methane (CH4) using Hess's Law, given the following reactions and enthalpy changes: 1. C(graphite) + 2H2(g) -> CH4(g) ΔH1 = -74.6 kJ/mol 2. 2H2(g) + O2(g) -> 2H2O(l) ΔH2 = -571.7 kJ/mol 3. C(graphite) + O2(g) -> CO2(g) ΔH3 = -393.5 kJ/mol.
answered
21 hours
ago
in
Chemical thermodynamics
by
ValRocha1287
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770
points)
0
votes
1
answer
35
views
Determine the standard enthalpy of formation of methane (CH4) given the following information: The standard enthalpy of formation of CO2 and H2O are -393.5 kJ/mol and -285.8 kJ/mol, respectively. The combustion of 0.50 g of methane in a bomb calorimeter resulted in a 1.20°C temperature increase of the surrounding water. The heat capacity of the bomb calorimeter is 5.85 kJ/°C.
answered
21 hours
ago
in
Chemical thermodynamics
by
AmberConaway
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730
points)
0
votes
1
answer
21
views
Determine the standard enthalpy of formation of ethanol (C2H5OH) given the following information: 1. The combustion of 1 mole of ethanol yields 1367 kJ of heat.2. The standard enthalpy of formation for CO2(g) and H2O(l) are -393.5 kJ/mol and -285.8 kJ/mol, respectively.
answered
21 hours
ago
in
Chemical thermodynamics
by
MindaCress0
(
310
points)
0
votes
1
answer
28
views
Determine the standard enthalpy of formation for propane (C3H8) using the following values: - C(graphite) + O2(g) → CO2(g) ΔH° = -393.5 kJ/mol- 2H2(g) + O2(g) → 2H2O(l) ΔH° = -572.4 kJ/mol- C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(l) ΔH° = -2220 kJ/mol
answered
21 hours
ago
in
Chemical thermodynamics
by
EnriquetaPat
(
350
points)
0
votes
1
answer
15
views
Determine the standard enthalpy of formation for methane (CH4) using the combustion reactions of methane and hydrogen gas (H2). Given the standard enthalpy of combustion for CH4 is -890.3 kJ/mol and the standard enthalpy of formation for H2O is -285.8 kJ/mol.
answered
21 hours
ago
in
Chemical thermodynamics
by
JonathonSala
(
550
points)
0
votes
1
answer
29
views
Determine the standard enthalpy of formation for hydrogen chloride gas using the following data:H2(g) + Cl2(g) → 2HCl(g) ΔH = -184.6 kJ/molH2(g) + 1/2O2(g) → H2O(l) ΔH = -285.8 kJ/mol2HCl(g) + O2(g) → 2ClO(g) + H2O(l) ΔH = -518.2 kJ/mol Note: The standard enthalpy of formation for a compound is the change in enthalpy that occurs when one mole of the compound is formed from its constituent elements, with all substances in their standard state at a given temperature (usually 25°C) and pressure (usually 1 atm).
answered
21 hours
ago
in
Chemical thermodynamics
by
TresaCole198
(
450
points)
0
votes
1
answer
28
views
Determine the standard enthalpy of formation for acetic acid (CH3COOH) using Hess's law and the following thermochemical equations:1) C(s) + O2(g) → CO2(g) ΔH = -394 kJ/mol2) 2H2(g) + O2(g) → 2H2O(l) ΔH = -572 kJ/mol3) C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(l) ΔH = -1234 kJ/mol4) CH3COOH(l) + O2(g) → CO2(g) + H2O(l) ΔH = ?
answered
21 hours
ago
in
Chemical thermodynamics
by
WaylonHebble
(
770
points)
0
votes
1
answer
31
views
Determine the standard enthalpy change of the reaction between 50.0 mL of 0.200 M hydrochloric acid (HCl) and 50.0 mL of 0.100 M sodium hydroxide (NaOH) at 25°C. The reaction is a neutralization reaction between HCl and NaOH, and the products are water and sodium chloride (NaCl). The molar enthalpy of formation of NaCl is -411.2 kJ/mol, and the specific heat capacity of the aqueous solution is 4.18 J/g°C.
answered
21 hours
ago
in
Chemical thermodynamics
by
AjaSchlink05
(
510
points)
0
votes
1
answer
32
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Determine the standard enthalpy change of the precipitation reaction between aqueous solutions of copper (II) sulfate and calcium hydroxide, given that the reaction produces copper (II) hydroxide, solid calcium sulfate and water as the products. The initial concentrations of the solutions are 0.1 M for copper (II) sulfate and 0.05 M for calcium hydroxide, and the reaction takes place at constant pressure and temperature of 25°C.
answered
21 hours
ago
in
Chemical thermodynamics
by
BrittneyDivi
(
570
points)
0
votes
1
answer
34
views
Determine the standard enthalpy change of the dissolution reaction of 2.50 g of NaOH in water, given that the molar enthalpy of hydration of Na+ and OH- ions are -406.8 kJ/mol and -230.0 kJ/mol respectively. The heat capacity of the calorimeter is 25.2 J/°C and the initial and final temperatures were 24.0°C and 29.2°C respectively.
answered
21 hours
ago
in
Chemical thermodynamics
by
ForrestFine0
(
550
points)
0
votes
1
answer
28
views
Determine the standard enthalpy change for the vaporization of 50g of ethyl alcohol (C2H5OH) at its normal boiling point of 78.4°C. Given that the molar heat of vaporization of ethyl alcohol is 38.56 kJ/mol and the molar mass of ethyl alcohol is 46.07 g/mol.
answered
21 hours
ago
in
Chemical thermodynamics
by
ToddPamphlet
(
590
points)
0
votes
1
answer
26
views
Determine the standard enthalpy change for the reaction: Fe2O3 (s) + 3CO (g) → 2Fe (s) + 3CO2 (g)given the following values of standard enthalpy of formation:ΔHf° [Fe2O3 (s)] = -824 kJ/mol ΔHf° [CO2 (g)] = -393.5 kJ/mol ΔHf° [CO (g)] = -110.5 kJ/mol ΔHf° [Fe (s)] = 0 kJ/mol
answered
21 hours
ago
in
Chemical thermodynamics
by
ArielBiddell
(
310
points)
0
votes
1
answer
38
views
Determine the standard enthalpy change for the reaction between calcium oxide and hydrochloric acid, given the following information:CaO(s) + 2HCl(aq) → CaCl2(aq) + H2O(l)∆Hf° CaCl2(aq) = -795.7 kJ/mol∆Hf° H2O(l) = -285.8 kJ/mol∆Hc° = -1922.6 kJ/mol
answered
21 hours
ago
in
Chemical thermodynamics
by
Hilario7169
(
490
points)
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Recent questions and answers in Chemical thermodynamics
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