To calculate the theoretical yield of 2,4-dichloronitrobenzene, we need to use the stoichiometry of the balanced chemical equation and the molar masses of the reactants and products.First, let's write the balanced chemical equation for the reaction:CHNO nitrobenzene + 2 Cl chlorine gas CHClNO 2,4-dichloronitrobenzene Next, we need to find the molar masses of nitrobenzene and 2,4-dichloronitrobenzene:Nitrobenzene CHNO : 6 12.01 + 5 1.01 + 1 14.01 + 2 16.00 = 123.11 g/mol2,4-Dichloronitrobenzene CHClNO : 6 12.01 + 3 1.01 + 2 35.45 + 1 14.01 + 2 16.00 = 202.02 g/molNow, we need to convert the given mass of nitrobenzene 10 g to moles:moles of nitrobenzene = mass / molar mass = 10 g / 123.11 g/mol = 0.0812 molAccording to the balanced chemical equation, 1 mole of nitrobenzene reacts with 2 moles of chlorine gas to produce 1 mole of 2,4-dichloronitrobenzene. Since we have excess chlorine gas, the limiting reactant is nitrobenzene.Now, we can calculate the theoretical yield of 2,4-dichloronitrobenzene:moles of 2,4-dichloronitrobenzene = moles of nitrobenzene = 0.0812 molFinally, we convert the moles of 2,4-dichloronitrobenzene to grams:mass of 2,4-dichloronitrobenzene = moles molar mass = 0.0812 mol 202.02 g/mol = 16.39 gThe theoretical yield of 2,4-dichloronitrobenzene that can be obtained from reacting 10 grams of nitrobenzene with excess chlorine gas is approximately 16.39 grams.