The balanced chemical equation for the preparation of 2,4-dichloronitrobenzene from nitrobenzene and chlorine gas is:C6H5NO2 + 2 Cl2 C6H3Cl2NO2 + 2 HClTo determine the amount of each reagent required to produce 10 grams of 2,4-dichloronitrobenzene, we will use stoichiometry.First, we need to calculate the molar mass of each compound:- Nitrobenzene C6H5NO2 : 6 12.01 + 5 1.01 + 14.01 + 2 16.00 = 123.11 g/mol- 2,4-Dichloronitrobenzene C6H3Cl2NO2 : 6 12.01 + 3 1.01 + 2 35.45 + 14.01 + 2 16.00 = 176.02 g/mol- Chlorine gas Cl2 : 2 35.45 = 70.90 g/molNow, we will calculate the moles of 2,4-dichloronitrobenzene required:10 g / 176.02 g/mol = 0.0568 molFrom the balanced chemical equation, we can see that 1 mole of nitrobenzene reacts with 2 moles of chlorine gas to produce 1 mole of 2,4-dichloronitrobenzene. Therefore, we need 0.0568 moles of nitrobenzene and 0.1136 moles of chlorine gas.Finally, we will convert the moles of each reagent to grams:- Nitrobenzene: 0.0568 mol 123.11 g/mol = 6.99 g- Chlorine gas: 0.1136 mol 70.90 g/mol = 8.06 gSo, to produce 10 grams of 2,4-dichloronitrobenzene, you will need 6.99 grams of nitrobenzene and 8.06 grams of chlorine gas.