The balanced chemical equation for the preparation of 2,4-dichloronitrobenzene from nitrobenzene and chlorine gas is:C6H5NO2 + 2 Cl2 C6H3Cl2NO2 + 2 HClTo calculate the theoretical yield, first determine the limiting reactant:1. Calculate the moles of nitrobenzene C6H5NO2 and chlorine gas Cl2 using their molar masses:Molar mass of nitrobenzene = 123.11 g/molMoles of nitrobenzene = 10 g / 123.11 g/mol = 0.0812 molMolar mass of chlorine gas = 70.90 g/molMoles of chlorine gas = 15 g / 70.90 g/mol = 0.2115 mol2. Determine the limiting reactant by comparing the mole ratios:The stoichiometric ratio of nitrobenzene to chlorine gas is 1:2. Mole ratio of nitrobenzene to chlorine gas = 0.0812 mol / 0.2115 mol = 0.384Since 0.384 is less than the required stoichiometric ratio of 0.5 1:2 , nitrobenzene is the limiting reactant.3. Calculate the theoretical yield of 2,4-dichloronitrobenzene C6H3Cl2NO2 :Moles of 2,4-dichloronitrobenzene = moles of nitrobenzene since the stoichiometric ratio is 1:1 = 0.0812 molMolar mass of 2,4-dichloronitrobenzene = 192.00 g/molTheoretical yield = moles of 2,4-dichloronitrobenzene molar mass of 2,4-dichloronitrobenzene = 0.0812 mol 192.00 g/mol = 15.59 gSo, the theoretical yield of 2,4-dichloronitrobenzene is 15.59 g.