The balanced chemical equation for the preparation of 2,4-dichloronitrobenzene from nitrobenzene and chlorine gas is:C6H5NO2 + 2 Cl2 C6H3Cl2NO2 + 2 HClTo determine the amount of each reactant required to produce 50g of 2,4-dichloronitrobenzene, we will use stoichiometry.First, we need to find the molar mass of each compound:- Nitrobenzene C6H5NO2 : 6 12.01 + 5 1.01 + 14.01 + 2 16.00 = 123.11 g/mol- Chlorine gas Cl2 : 2 35.45 = 70.90 g/mol- 2,4-Dichloronitrobenzene C6H3Cl2NO2 : 6 12.01 + 3 1.01 + 2 35.45 + 14.01 + 2 16.00 = 197.00 g/molNow, we can use stoichiometry to find the amount of each reactant needed:1. Calculate the moles of 2,4-dichloronitrobenzene needed:50 g C6H3Cl2NO2 1 mol C6H3Cl2NO2 / 197.00 g C6H3Cl2NO2 = 0.254 mol C6H3Cl2NO22. Use the balanced equation to find the moles of nitrobenzene and chlorine gas needed:0.254 mol C6H3Cl2NO2 1 mol C6H5NO2 / 1 mol C6H3Cl2NO2 = 0.254 mol C6H5NO20.254 mol C6H3Cl2NO2 2 mol Cl2 / 1 mol C6H3Cl2NO2 = 0.508 mol Cl23. Convert moles of each reactant to grams:0.254 mol C6H5NO2 123.11 g C6H5NO2 / 1 mol C6H5NO2 = 31.27 g C6H5NO20.508 mol Cl2 70.90 g Cl2 / 1 mol Cl2 = 36.02 g Cl2So, to produce 50g of 2,4-dichloronitrobenzene, you will need 31.27g of nitrobenzene and 36.02g of chlorine gas.