Recent questions in Chemistry

0 votes

1 answer 57 views

Calculate the change in internal energy of a system that releases 350 J of heat to the surroundings and does 200 J of work on its surroundings?

asked Jan 23 in Physical Chemistry by WFBMonty0506 (230 points)

0 votes

1 answer 49 views

Calculate the change in Gibbs free energy for the reaction between hydrogen gas and iodine gas that forms hydrogen iodide gas. The balanced equation is as follows:H2(g) + I2(g) → 2HI(g)Assume a temperature of 298 K and use the following standard molar free energy of formation values:∆Gf° (HI) = -17.4 kJ/mol∆Gf° (H2) = 0 kJ/mol∆Gf° (I2) = 0 kJ/mol

asked Jan 23 in Chemical thermodynamics by AbrahamMaruf (390 points)

0 votes

1 answer 59 views

Calculate the change in Gibbs free energy for the electrochemical reaction, given the standard reduction potentials of the reactants and products:Cu2+ (aq) + 2e- → Cu (s)E° = +0.34 VFe2+ (aq) + 2e- → Fe (s)E° = -0.44 V

asked Jan 23 in ElectroChemistry by OscarHiggins (370 points)

0 votes

1 answer 52 views

Calculate the change in entropy when 1 mole of methane gas (CH4) is burned completely in oxygen gas (O2) at constant pressure and 298 K.

asked Jan 23 in Chemical thermodynamics by MXNCorine215 (270 points)

0 votes

1 answer 61 views

Calculate the change in entropy when 1 mole of an ideal gas is compressed from 4 L to 1 L irreversibly at a temperature of 298 K.

asked Jan 23 in Physical Chemistry by Nelle562245 (550 points)

0 votes

1 answer 50 views

Calculate the change in entropy of the system when 2 moles of ammonia react to form 3 moles of hydrogen gas and 1 mole of nitrogen gas. The reaction takes place at a constant temperature of 298 K and at a pressure of 1 atm. The molar entropy of each component in the reaction is given below:Ammonia: 192.5 J/K·molHydrogen gas: 130.6 J/K·molNitrogen gas: 191.6 J/K·mol

asked Jan 23 in Chemical thermodynamics by PeteMonckton (460 points)

0 votes

1 answer 65 views

Calculate the change in entropy for the reaction: 2H2(g) + O2(g) → 2H2O(g)if the standard entropy values of H2, O2, and H2O are 130.7 J/mol*K, 205.0 J/mol*K, and 188.7 J/mol*K, respectively.

asked Jan 23 in Inorganic Chemistry by AntoinetteHo (370 points)

0 votes

1 answer 58 views

Calculate the change in entropy for the combustion of methane gas (CH4) at constant pressure and temperature of 298 K. The products of the reaction are carbon dioxide gas (CO2) and water vapor (H2O). The molar entropy of CH4, CO2 and H2O at 298 K are 186.3 J/K/mol, 213.7 J/K/mol, and 188.8 J/K/mol, respectively.

asked Jan 23 in Chemical thermodynamics by ChadwickDalz (270 points)

0 votes

1 answer 58 views

Calculate the change in entropy and enthalpy for the reaction of iron (III) oxide with carbon monoxide to form iron and carbon dioxide, given the following information:Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g)ΔH°f (Fe2O3) = -824.2 kJ/molΔH°f (CO) = -110.5 kJ/molΔH°f (Fe) = 0 kJ/molΔH°f (CO2) = -393.5 kJ/molΔS° (Fe2O3) = 87.4 J/K molΔS° (CO) = 197.9 J/K molΔS° (Fe) = 27.3 J/K molΔS° (CO2) = 213.6 J/K mol

asked Jan 23 in Inorganic Chemistry by ChadwickBurl (290 points)

0 votes

1 answer 52 views

Calculate the change in entropy (ΔS) of the following reaction at 298 K:2SO2(g) + O2(g) → 2SO3(g) Given the standard molar entropies at 298 K: ΔS°(SO2,g) = 248.2 J/Kmol ΔS°(O2,g) = 205.0 J/Kmol ΔS°(SO3,g) = 256.2 J/Kmol

asked Jan 23 in Chemical thermodynamics by LaurindaRake (290 points)

0 votes

1 answer 49 views

Calculate the change in entropy (ΔS) for the reaction in which 3 moles of carbon monoxide (CO) gas is burned with excess oxygen gas to form 3 moles of carbon dioxide (CO2) gas. The reaction is carried out at constant pressure and a temperature of 298 K.

asked Jan 23 in Inorganic Chemistry by AliF33136418 (270 points)

0 votes

1 answer 62 views

Calculate the change in entropy (in J/K) for the following reaction at 298 K: 2CH3OH (l) + 3O2 (g) → 2CO2 (g) + 4H2O (l) Given the following standard entropy values (in J/K): CH3OH (l): 126.6, O2 (g): 205.0, CO2 (g): 213.6, H2O (l): 69.9

asked Jan 23 in Chemical thermodynamics by Renate88465 (350 points)

0 votes

1 answer 54 views

Calculate the change in enthalpy for the reaction CH4 (g) + 2O2 (g) → CO2 (g) + 2H2O (l) given that the enthalpies of formation for CH4 (g), CO2 (g) and H2O (l) are -74.81 kJ/mol, -393.51 kJ/mol and -285.83 kJ/mol respectively.

asked Jan 23 in Physical Chemistry by MiraFossey3 (330 points)

0 votes

1 answer 56 views

Calculate the change in enthalpy for the following chemical reaction: CH4(g) + 2O2(g) -> CO2(g) + 2H2O(l) Given that the enthalpies of formation for CH4(g), CO2(g), and H2O(l) are -74.8 kJ/mol, -393.5 kJ/mol, and -285.8 kJ/mol respectively.

asked Jan 23 in Chemical reactions by JaniTinker23 (210 points)

0 votes

1 answer 54 views

Calculate the change in enthalpy for the combustion of 2 moles of methane gas (CH4) at a constant pressure of 1 atmosphere and a temperature of 298 K. Given the standard enthalpy of formation for methane is -74.81 kJ/mol.

asked Jan 23 in Physical Chemistry by KristinaCont (230 points)

0 votes

1 answer 55 views

Calculate the change in enthalpy and entropy for the reaction Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g) at 25°C given the following data:- ΔH°f for MgCl2(aq) = -641.3 kJ/mol- ΔS°f for MgCl2(aq) = -200.9 J/K/mol- ΔH°f for H2(g) = 0 kJ/mol- ΔS°f for H2(g) = 130.7 J/K/mol- ΔH°f for HCl(aq) = -167 kJ/mol- ΔS°f for HCl(aq) = -18.8 J/K/mol- ΔH°f for Mg(s) = 0 kJ/mol- ΔS°f for Mg(s) = 32.7 J/K/molAssume that ΔH°f and ΔS°f are independent of temperature.

asked Jan 23 in Inorganic Chemistry by TammieDancy (350 points)

0 votes

1 answer 53 views

Calculate the change in enthalpy (ΔH) for the following reaction at 25°C given the standard enthalpies of formation for each compound: 2H2(g) + O2(g) → 2H2O(g) Standard enthalpies of formation: ΔHf° (H2O)(g) = -241.82 kJ/molΔHf° (H2)(g) = 0 kJ/molΔHf° (O2)(g) = 0 kJ/mol

asked Jan 23 in Physical Chemistry by DongBunn9830 (410 points)

0 votes

1 answer 57 views

Calculate the change in enthalpy (ΔH) for the combustion of methane gas (CH4) at 25°C and constant pressure of 1 atm. The equation for the combustion of methane is:CH4 (g) + 2O2 (g) → CO2 (g) + 2H2O (l) Given the standard enthalpies of formation at 25°C are:ΔHf[CH4 (g)] = -74.87 kJ/mol ΔHf[CO2 (g)] = -393.5 kJ/mol ΔHf[H2O (l)] = -285.8 kJ/mol Assume that water is in its liquid phase at the end of the reaction.

asked Jan 23 in Physical Chemistry by FerdinandHoo (410 points)

0 votes

1 answer 58 views

Calculate the change in enthalpy (ΔH) for the combustion of 10 grams of propane (C3H8) if the heat released by the reaction is -2202 kJ.

asked Jan 23 in Chemical reactions by BennieBrasse (350 points)

0 votes

1 answer 56 views

Calculate the cell potential for the reaction:Hg2Cl2(s) + 2 Cl-(aq) → 2 Hg(l) + 2 Cl2(g)Given the standard reduction potentials: Hg2Cl2(s) + 2 e- → 2 Hg(l) + 2 Cl-(aq) E° = 0.268 VCl2(g) + 2 e- → 2 Cl-(aq) E° = 1.36 V

asked Jan 23 in ElectroChemistry by LavinaBatman (590 points)

Categories