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Calculate the rate of electroplating of copper on a metallic surface at a current of 2.5 amperes for a duration of 3 hours using a copper nitrate solution with a concentration of 0.2 M. Given that the standard potential of the reduction reaction of Cu2+ to Cu is +0.34 V and the charge of one mole of electrons is 96500 C/mol.

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To calculate the rate of electroplating of copper on a metallic surface, we need to determine the amount of copper deposited during the electroplating process. We can use Faraday's law of electrolysis to do this.Faraday's law states that the amount of substance deposited during electrolysis is directly proportional to the amount of charge passed through the solution. Mathematically, it can be represented as:mass of substance deposited  m  =  current  I   time  t   molar mass  M   /  n  Faraday's constant  F  where:- m is the mass of the substance deposited  in grams - I is the current  in amperes - t is the time  in seconds - M is the molar mass of the substance  in grams per mole - n is the number of electrons involved in the redox reaction  in moles - F is Faraday's constant  96500 C/mol First, we need to determine the number of electrons involved in the reduction reaction of Cu to Cu. The balanced half-reaction is:Cu + 2e  CuSo, n = 2 moles of electrons are involved in the reaction.Next, we need to convert the time from hours to seconds:3 hours   3600 seconds/hour  = 10800 secondsNow, we can use Faraday's law to calculate the mass of copper deposited:m =  I  t  M  /  n  F m =  2.5 A  10800 s  63.55 g/mol  /  2 mol  96500 C/mol m =  2.5  10800  63.55  /  2  96500 m  45.6 gSo, 45.6 grams of copper are deposited on the metallic surface during the electroplating process.To calculate the rate of electroplating, we can divide the mass of copper deposited by the total time:rate of electroplating = mass of copper deposited / timerate of electroplating = 45.6 g / 3 hoursrate of electroplating  15.2 g/hourTherefore, the rate of electroplating of copper on the metallic surface is approximately 15.2 grams per hour.

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