Question

Calculate the rate constant at 300 K for a gas phase reaction with a rate of 0.025 M/s and an initial concentration of 0.10 M. The reaction is second order in the concentration of reactants.

Answer 1

For a second-order reaction, the rate law is given by:rate = k[A]^2where rate is the reaction rate, k is the rate constant, and [A] is the concentration of the reactant.We are given the rate  0.025 M/s  and the initial concentration of the reactant  0.10 M . We can now solve for the rate constant  k :0.025 M/s = k 0.10 M ^2To solve for k, divide both sides by  0.10 M ^2:k =  0.025 M/s  /  0.10 M ^2k =  0.025 M/s  /  0.01 M^2 k = 2.5 M^-1 s^-1 So, the rate constant  k  at 300 K for this gas phase reaction is 2.5 M^-1 s^-1 .