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ago in ElectroChemistry by (410 points)
Calculate the power output of a galvanic cell having a standard potential of +0.76V and a current of 0.5A flowing through it. The cell consists of a zinc electrode and a copper electrode connected by a salt bridge and the concentration of the electrolyte is 1.0M. Given that the Faraday constant is 96487 C/mol and the temperature is 298K.

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To calculate the power output of the galvanic cell, we can use the formula:Power  P  = Voltage  V   Current  I We are given the standard potential  E  of the cell as +0.76 V and the current  I  as 0.5 A. Since the concentration of the electrolyte is 1.0 M, we can assume that the cell potential  E  is approximately equal to the standard potential  E . This is because the Nernst equation, which relates the cell potential to the standard potential and concentrations, simplifies to E = E when concentrations are 1.0 M.So, we can use the given values to calculate the power output:P = E  IP = 0.76 V  0.5 AP = 0.38 WTherefore, the power output of the galvanic cell is 0.38 watts.

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