Question

Calculate the power output for a Zinc-Copper electrochemical cell operating at standard conditions with a Zinc electrode that measures 10 cm by 12 cm and a Copper electrode that measures 8 cm by 10 cm. The current flowing through the circuit is 0.5 A. The standard reduction potentials for the half-reactions are +0.76 V for Cu2+/Cu and -0.76 V for Zn2+/Zn.

Answer 1

To calculate the power output of the Zinc-Copper electrochemical cell, we first need to determine the cell potential  E_cell  using the standard reduction potentials of the half-reactions.E_cell = E_red cathode  - E_red anode In this case, the Copper electrode is the cathode, and the Zinc electrode is the anode. Therefore, we can plug in the standard reduction potentials:E_cell =  +0.76 V  -  -0.76 V  = 1.52 VNow that we have the cell potential, we can calculate the power output  P  using the formula:P = I  E_cellWhere I is the current flowing through the circuit  0.5 A  and E_cell is the cell potential  1.52 V .P =  0.5 A    1.52 V  = 0.76 WSo, the power output for the Zinc-Copper electrochemical cell operating at standard conditions is 0.76 watts.