To calculate the theoretical yield of benzocaine, we need to use stoichiometry. First, we need to know the balanced chemical equation for the reaction:p-aminobenzoic acid + ethanol benzocaine + waterNow, we need the molar masses of p-aminobenzoic acid and benzocaine:p-aminobenzoic acid C7H7NO2 : 7 12.01 + 7 1.01 + 1 14.01 + 2 16.00 = 137.14 g/molbenzocaine C9H11NO2 : 9 12.01 + 11 1.01 + 1 14.01 + 2 16.00 = 165.19 g/molNext, we need to convert the mass of p-aminobenzoic acid to moles:5 g p-aminobenzoic acid 1 mol p-aminobenzoic acid / 137.14 g p-aminobenzoic acid = 0.0364 mol p-aminobenzoic acidSince the stoichiometry of the reaction is 1:1, the moles of benzocaine produced will be equal to the moles of p-aminobenzoic acid:0.0364 mol p-aminobenzoic acid 1 mol benzocaine / 1 mol p-aminobenzoic acid = 0.0364 mol benzocaineFinally, we convert the moles of benzocaine to grams:0.0364 mol benzocaine 165.19 g benzocaine / 1 mol benzocaine = 6.01 g benzocaineThe theoretical yield of benzocaine that can be produced from 5 grams of p-aminobenzoic acid and excess ethanol in the preparation process is 6.01 grams.