To calculate the theoretical yield of benzocaine, we need to first determine the limiting reagent in the reaction. We will do this by calculating the moles of each reactant and comparing their mole ratios.1. Calculate the moles of p-aminobenzoic acid PABA and ethanol:Molecular weight of PABA = 137.14 g/mol C7H7NO2 Molecular weight of ethanol = 46.07 g/mol C2H5OH Given: 5 grams of PABA and 25 mL of ethanolDensity of ethanol = 0.789 g/mLMass of ethanol = volume density = 25 mL 0.789 g/mL = 19.725 gNow, we can calculate the moles of each reactant:Moles of PABA = mass / molecular weight = 5 g / 137.14 g/mol = 0.0364 molMoles of ethanol = mass / molecular weight = 19.725 g / 46.07 g/mol = 0.428 mol2. Determine the limiting reagent:The balanced chemical equation for the synthesis of benzocaine from PABA and ethanol is:PABA + C2H5OH C9H11NO2 + H2OFrom the balanced equation, we can see that the mole ratio of PABA to ethanol is 1:1.Mole ratio of PABA to ethanol in the reaction mixture = 0.0364 mol / 0.428 mol = 0.085Since the mole ratio is less than 1, PABA is the limiting reagent.3. Calculate the theoretical yield of benzocaine:Molecular weight of benzocaine = 165.19 g/mol C9H11NO2 Using the moles of the limiting reagent PABA , we can calculate the moles of benzocaine produced:Moles of benzocaine = moles of PABA = 0.0364 molNow, we can calculate the theoretical yield of benzocaine:Theoretical yield = moles of benzocaine molecular weight of benzocaineTheoretical yield = 0.0364 mol 165.19 g/mol = 6.01 gTherefore, the theoretical yield of benzocaine that can be obtained from the reaction is 6.01 grams, assuming a complete reaction and 100% yield.