To calculate the yield of benzocaine, we first need to determine the molecular weights of p-aminobenzoic acid and benzocaine. The molecular weight of p-aminobenzoic acid C7H7NO2 is:C: 12.01 g/mol * 7 = 84.07 g/molH: 1.01 g/mol * 7 = 7.07 g/molN: 14.01 g/mol * 1 = 14.01 g/molO: 16.00 g/mol * 2 = 32.00 g/molTotal: 84.07 + 7.07 + 14.01 + 32.00 = 137.15 g/molThe molecular weight of benzocaine C9H11NO2 is:C: 12.01 g/mol * 9 = 108.09 g/molH: 1.01 g/mol * 11 = 11.11 g/molN: 14.01 g/mol * 1 = 14.01 g/molO: 16.00 g/mol * 2 = 32.00 g/molTotal: 108.09 + 11.11 + 14.01 + 32.00 = 165.21 g/molNow, we can use stoichiometry to determine the yield of benzocaine. Since we have excess ethanol, the reaction will be limited by the amount of p-aminobenzoic acid. The stoichiometry of the reaction is 1:1, meaning one mole of p-aminobenzoic acid will produce one mole of benzocaine.First, we need to convert the 10 grams of p-aminobenzoic acid to moles:10 g / 137.15 g/mol = 0.0729 molesSince the stoichiometry is 1:1, we will also have 0.0729 moles of benzocaine produced. Now, we can convert this back to grams:0.0729 moles * 165.21 g/mol = 12.03 gSo, assuming a perfect reaction and no loss of product during workup, the yield of benzocaine from 10 grams of p-aminobenzoic acid would be approximately 12.03 grams.