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What is the expected yield of benzocaine if 5 grams of p-aminobenzoic acid and 10 mL of ethanol are used in the preparation of benzocaine?

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To calculate the expected yield of benzocaine, we first need to determine the limiting reagent in the reaction. The reaction between p-aminobenzoic acid and ethanol to form benzocaine is as follows:p-aminobenzoic acid + ethanol  benzocaine + waterFirst, we need to find the moles of each reactant:1. p-aminobenzoic acid: Molecular weight = 137.14 g/mol5 g of p-aminobenzoic acid = 5 g / 137.14 g/mol = 0.0364 mol2. Ethanol:Molecular weight = 46.07 g/molDensity of ethanol = 0.789 g/mL10 mL of ethanol = 10 mL * 0.789 g/mL = 7.89 g7.89 g of ethanol = 7.89 g / 46.07 g/mol = 0.171 molNow, we need to determine the limiting reagent. The stoichiometry of the reaction is 1:1, so we can compare the moles of each reactant:0.0364 mol p-aminobenzoic acid : 0.171 mol ethanolSince p-aminobenzoic acid is present in a smaller amount, it is the limiting reagent.Now, we can calculate the expected yield of benzocaine:Moles of benzocaine = moles of limiting reagent = 0.0364 molMolecular weight of benzocaine = 165.19 g/molExpected yield of benzocaine = 0.0364 mol * 165.19 g/mol = 6.01 gSo, the expected yield of benzocaine is approximately 6.01 grams.
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