To solve this problem, we need to first determine the reaction between hydrochloric acid HCl and sodium hydroxide NaOH . The reaction is a neutralization reaction, which can be written as:HCl + NaOH NaCl + H2ONow, we need to find the limiting reactant. Since there are 0.1 mol of HCl and 0.2 mol of NaOH, HCl is the limiting reactant. The reaction will consume all 0.1 mol of HCl and 0.1 mol of NaOH, leaving 0.1 mol of NaOH in excess.Next, we need to find the concentration of the excess NaOH in the solution. To do this, we need to know the volume of the solution. However, the problem does not provide the volume. Assuming that the volumes of the HCl and NaOH solutions are equal, we can still determine the pH of the resulting solution.Since there is an excess of 0.1 mol of NaOH, the solution will be basic. To find the pH, we first need to find the pOH. The pOH can be calculated using the formula:pOH = -log10[OH-]Since we don't have the volume, we can't find the exact concentration of OH- ions. However, we know that the concentration of OH- ions will be greater than the concentration of H+ ions, making the solution basic.In a basic solution, the pOH is less than 7. To find the pH, we can use the relationship:pH + pOH = 14Since pOH < 7, the pH will be greater than 7. Therefore, the pH of the resulting solution will be greater than 7, indicating a basic solution.