The balanced chemical equation for the neutralization of hydrochloric acid HCl with sodium hydroxide NaOH is:HCl aq + NaOH aq NaCl aq + H2O l To find the concentration of the resulting sodium chloride NaCl solution, we can use the formula:M1V1 = M2V2where M1 and V1 are the molarity and volume of the first solution HCl , and M2 and V2 are the molarity and volume of the second solution NaOH .First, we need to determine the moles of HCl and NaOH:moles of HCl = M1 V1 = 0.1 M 0.025 L = 0.0025 molesmoles of NaOH = M2 V2 = 0.05 M 0.05 L = 0.0025 molesSince the moles of HCl and NaOH are equal, the reaction goes to completion, and all the HCl and NaOH will react to form NaCl and water.Now, we can find the concentration of the resulting NaCl solution. The total volume of the solution is the sum of the volumes of HCl and NaOH:V_total = V1 + V2 = 0.025 L + 0.05 L = 0.075 LSince all the HCl and NaOH reacted to form NaCl, the moles of NaCl will be equal to the moles of HCl or NaOH:moles of NaCl = 0.0025 molesNow, we can find the concentration of NaCl:M_NaCl = moles of NaCl / V_total = 0.0025 moles / 0.075 L = 0.0333 MSo, the concentration of the resulting sodium chloride solution is 0.0333 M.