To solve this problem, we need to determine the amount of HCl and NaOH in moles, and then find out which one is in excess. After that, we can calculate the concentration of the excess and determine the pH or pOH of the solution.1. Calculate the moles of HCl and NaOH:moles of HCl = volume L concentration M moles of HCl = 0.025 L 0.1 M = 0.0025 molesmoles of NaOH = volume L concentration M moles of NaOH = 0.05 L 0.05 M = 0.0025 moles2. Determine the excess reactant:In this case, the moles of HCl and NaOH are equal, so they will completely neutralize each other, and there will be no excess reactant. The resulting solution will be neutral.3. Calculate the pH of the solution:Since the solution is neutral, the pH will be 7.