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Calculate the amount of heat (in joules) released when 50 ml of 0.1 M hydrochloric acid (HCl) is mixed with 50 ml of 0.1 M sodium hydroxide (NaOH) at a constant pressure and a temperature of 25°C. The heat of neutralization of HCl and NaOH is -57.1 kJ/mol.

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To calculate the amount of heat released, we first need to determine the number of moles of HCl and NaOH reacting in the neutralization reaction.The reaction between HCl and NaOH is as follows:HCl aq  + NaOH aq   NaCl aq  + H2O l Since both solutions have the same concentration  0.1 M  and volume  50 ml , they will react in a 1:1 ratio.First, we need to convert the volume of the solutions to liters:50 ml = 0.050 LNext, we can calculate the number of moles of HCl and NaOH using the given concentration:moles of HCl =  0.1 mol/L   0.050 L = 0.005 molmoles of NaOH =  0.1 mol/L   0.050 L = 0.005 molNow, we can use the heat of neutralization  -57.1 kJ/mol  to calculate the amount of heat released:heat released =  0.005 mol    -57.1 kJ/mol heat released = -0.2855 kJSince 1 kJ = 1000 J, we can convert the heat released to joules:heat released = -0.2855 kJ  1000 J/kJheat released = -285.5 JSo, the amount of heat released when 50 ml of 0.1 M HCl is mixed with 50 ml of 0.1 M NaOH is -285.5 J. The negative sign indicates that the reaction is exothermic, meaning heat is released to the surroundings.

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