To calculate the heat of neutralization, we can use the formula:q = mcTwhere q is the heat of neutralization, m is the mass of the solution, c is the specific heat capacity of the solution, and T is the temperature change.First, we need to find the mass of the solution. Since the density of the solution is close to that of water 1 g/mL , we can assume that the mass of the solution is equal to the combined volume of the two solutions:mass = volume of HCl + volume of NaOH = 25 mL + 25 mL = 50 mLSince the density is approximately 1 g/mL, the mass is approximately 50 g.Next, we need the specific heat capacity of the solution. We can assume that the specific heat capacity is close to that of water, which is 4.18 J/gC.Now we can plug in the values into the formula:q = 50 g 4.18 J/gC 5.0C q = 1045 JThe heat of neutralization is approximately 1045 J.