To calculate the standard enthalpy change for the neutralization reaction, we need to first determine the heat released during the reaction q and then divide by the moles of the limiting reactant.The balanced equation for the neutralization reaction is:HCl aq + NaOH aq NaCl aq + H2O l Since both reactants have the same concentration and volume, they will react in a 1:1 ratio, and neither is in excess.First, let's find the heat released q using the formula:q = mcTwhere m is the mass of the solution, c is the specific heat capacity, and T is the temperature change.The total volume of the solution is 25.0 mL + 25.0 mL = 50.0 mL. Assuming the density of the solution is approximately 1 g/mL similar to water , the mass of the solution is 50.0 g.Now, we can calculate q:q = 50.0 g 4.18 J/gC 5.0C = 1045 JNext, we need to determine the moles of the limiting reactant. We can use the volume and concentration of either HCl or NaOH since they react in a 1:1 ratio.moles = volume concentration = 0.025 L 0.100 mol/L = 0.00250 molFinally, we can calculate the standard enthalpy change H by dividing the heat released by the moles of the limiting reactant:H = q / moles = 1045 J / 0.00250 mol = 418000 J/mol = 418 kJ/molThe standard enthalpy change for the neutralization of 25.0 mL of 0.100 M hydrochloric acid with 25.0 mL of 0.100 M sodium hydroxide is 418 kJ/mol.