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What is the standard enthalpy change for the sublimation of iodine (I2) given that the standard enthalpy change of formation of iodine molecules is -62.4 kJ/mol and the enthalpy of vaporization of iodine is 41.7 kJ/mol?

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The standard enthalpy change for the sublimation of iodine  I2  can be calculated by adding the standard enthalpy change of formation of iodine molecules and the enthalpy of vaporization of iodine.Sublimation is the process of a solid changing directly into a gas, bypassing the liquid phase. In this case, we are given the standard enthalpy change of formation of iodine molecules  -62.4 kJ/mol  and the enthalpy of vaporization of iodine  41.7 kJ/mol .The standard enthalpy change for sublimation  H_sub  can be calculated using the following equation:H_sub = H_f + H_vapwhere H_f is the standard enthalpy change of formation and H_vap is the enthalpy of vaporization.Plugging in the given values:H_sub =  -62.4 kJ/mol  +  41.7 kJ/mol H_sub = -20.7 kJ/molTherefore, the standard enthalpy change for the sublimation of iodine  I2  is -20.7 kJ/mol.

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