The standard enthalpy change H for the sublimation of iodine I2 can be calculated by adding the heats of fusion and vaporization together. This is because sublimation is the process of a solid converting directly into a gas, which involves both fusion solid to liquid and vaporization liquid to gas .H sublimation = H fusion + H vaporization Given the heats of fusion and vaporization of iodine are 15.5 kJ/mol and 41.7 kJ/mol respectively, we can calculate the standard enthalpy change for sublimation:H sublimation = 15.5 kJ/mol + 41.7 kJ/mol = 57.2 kJ/molSo, the standard enthalpy change for the sublimation of iodine I2 at 298 K is 57.2 kJ/mol.