To calculate the standard enthalpy change for the sublimation of iodine, we need to consider the enthalpy changes for both fusion and vaporization. Sublimation is the process of a solid turning directly into a gas, bypassing the liquid phase. In this case, iodine I2 will first undergo fusion melting and then vaporization boiling .The enthalpy change for sublimation H_sub can be calculated by adding the enthalpy of fusion H_fus and the enthalpy of vaporization H_vap :H_sub = H_fus + H_vapGiven the enthalpy of fusion for iodine is 15.52 kJ/mol and the enthalpy of vaporization for iodine is 41.57 kJ/mol, we can plug these values into the equation:H_sub = 15.52 kJ/mol + 41.57 kJ/molH_sub = 57.09 kJ/molTherefore, the standard enthalpy change for the sublimation of iodine I2 is 57.09 kJ/mol.