The resonance structure of benzene C6H6 consists of two equivalent structures, where each carbon atom is bonded to two other carbon atoms by single and double bonds, and to one hydrogen atom. In the first structure, the double bonds are between carbon atoms 1-2, 3-4, and 5-6, while in the second structure, the double bonds are between carbon atoms 2-3, 4-5, and 6-1. These two structures are in resonance with each other, meaning that the actual structure of benzene is a hybrid of the two.The resonance in benzene contributes to its stability in several ways:1. Delocalization of electrons: The electrons in the double bonds are not confined to a specific pair of carbon atoms but are instead delocalized across all six carbon atoms in the ring. This delocalization of electrons results in a more stable structure, as the electrons are distributed evenly across the entire molecule.2. Lower energy state: The resonance hybrid structure of benzene has a lower overall energy state than either of the individual resonance structures. This lower energy state makes the molecule more stable and less reactive than if it existed in only one of the resonance structures.3. Aromaticity: Benzene is an aromatic compound, which means it has a closed loop of delocalized electrons that follow the 4n+2 rule where n is an integer . In the case of benzene, n=1, and there are six delocalized electrons. Aromatic compounds are generally more stable than their non-aromatic counterparts due to the delocalization of electrons and the lower energy state of the molecule.In summary, the resonance structure of benzene contributes to its stability by delocalizing electrons across the entire molecule, resulting in a lower energy state and increased stability due to its aromatic nature.