0 votes
41 views
in Organic Chemistry by (410 points)
What is the hybridization state of the carbon atoms in benzene and how does it contribute to the stability of the molecule?

1 Answer

0 votes
by (230 points)
In benzene  C6H6 , each carbon atom is bonded to two other carbon atoms and one hydrogen atom. The hybridization state of the carbon atoms in benzene is sp2.In sp2 hybridization, one s orbital and two p orbitals of the carbon atom mix to form three new sp2 hybrid orbitals. These sp2 hybrid orbitals are arranged in a trigonal planar geometry, with bond angles of approximately 120 degrees. Each carbon atom in benzene forms three sigma    bonds: one with a hydrogen atom and two with adjacent carbon atoms.The remaining unhybridized p orbital on each carbon atom is perpendicular to the plane of the molecule and overlaps with the p orbitals of the adjacent carbon atoms. This overlap forms six pi    bonds, which are delocalized over the entire benzene ring. This delocalization of electrons is known as resonance or aromaticity, and it contributes significantly to the stability of the benzene molecule.The stability of benzene due to its aromaticity can be observed in its resistance to reactions that would typically break double bonds in other molecules. This stability is also reflected in its heat of hydrogenation, which is lower than expected for a molecule with three isolated double bonds. Overall, the sp2 hybridization and the delocalization of  electrons in benzene contribute to its unique stability and chemical properties.
Welcome to Sarvan Science Q&A, where you can ask questions and receive answers from other members of the community.
...