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What is the resonance hybrid structure of benzene? Show how the pi electrons are distributed throughout the molecule and explain why it is unusually stable compared to other unsaturated compounds.

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The resonance hybrid structure of benzene is a hexagonal ring of six carbon atoms, with each carbon atom bonded to two other carbon atoms and one hydrogen atom. The carbon-carbon bonds in benzene are intermediate between single and double bonds, with a bond length of about 1.40 . This is shorter than a typical single bond  1.54   but longer than a typical double bond  1.34  .The pi electrons in benzene are distributed evenly throughout the molecule, forming a continuous cloud of electron density above and below the plane of the carbon atoms. This delocalization of the pi electrons is represented by two resonance structures, where each carbon atom has a double bond with one of its neighbors in an alternating pattern. The true structure of benzene is a hybrid of these two resonance forms, with the pi electrons shared equally among all six carbon atoms.The unusual stability of benzene compared to other unsaturated compounds can be attributed to this delocalization of pi electrons. In a typical unsaturated compound, the pi electrons are localized between two carbon atoms, forming a double bond. This localization of electron density makes the molecule more reactive and less stable. In benzene, however, the pi electrons are spread out over the entire ring, which reduces the electron density at any one location and makes the molecule less reactive. This delocalization also results in a lower overall energy for the molecule, contributing to its stability.Additionally, benzene's stability is further enhanced by its symmetrical structure and the fact that all carbon atoms are sp2 hybridized, which allows for the formation of strong sigma bonds between the carbon atoms. This combination of factors makes benzene significantly more stable than other unsaturated compounds.
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