The bond order of the NO molecule can be determined by looking at its molecular orbital diagram and calculating the difference between the number of electrons in bonding and antibonding orbitals, divided by 2.NO has a total of 15 electrons 7 from nitrogen and 8 from oxygen . In the molecular orbital diagram, the electrons fill up the orbitals in the following order: 1s, *1s, 2s, *2s, 2px, 2py, and 2pz.The bonding orbitals are 1s, 2s, 2px, 2py, and 2pz, which contain a total of 12 electrons. The antibonding orbitals are *1s and *2s, which contain a total of 3 electrons.Bond order = number of electrons in bonding orbitals - number of electrons in antibonding orbitals / 2Bond order = 12 - 3 / 2Bond order = 9 / 2Bond order = 4.5Therefore, the bond order of the NO molecule is 4.5.