The bond order of the nitrogen-oxygen bond in the NO molecule can be determined by analyzing its molecular orbital diagram. Nitrogen has 7 electrons, and oxygen has 8 electrons, giving a total of 15 electrons for the NO molecule.To calculate the bond order, we can use the formula:Bond order = number of electrons in bonding orbitals - number of electrons in antibonding orbitals / 2For NO, the molecular orbital configuration is:1s, *1s, 2s, *2s, 2p^4, 2p, *2pThere are 10 electrons in bonding orbitals 1s, 2s, 2p^4, 2p and 5 electrons in antibonding orbitals *1s, *2s, *2p .Using the formula:Bond order = 10 - 5 / 2 = 5 / 2 = 2.5So, the bond order of the nitrogen-oxygen bond in the NO molecule is 2.5.