In the compound NaClO3 sodium chlorate , the oxidation states of each element are as follows:1. Sodium Na : +12. Chlorine Cl : +53. Oxygen O : -2Here's the breakdown of how we determine these oxidation states:- Sodium is in Group 1 of the periodic table, and elements in this group have an oxidation state of +1.- Oxygen is in Group 16, and elements in this group typically have an oxidation state of -2.- To determine the oxidation state of chlorine, we can use the formula for the compound: NaClO3. Since there is one sodium atom +1 and three oxygen atoms -2 each , the total oxidation state of the compound should be 0 as it is a neutral compound . Therefore, the oxidation state of chlorine can be calculated as follows: +1 + x + 3 -2 = 0 x - 6 = -1 x = +5So, the oxidation state of chlorine in NaClO3 is +5.