In the compound NH4NO3, there are two different nitrogen atoms with different oxidation states. In the ammonium ion NH4+ , the nitrogen atom has an oxidation state of -3. This is because hydrogen has an oxidation state of +1, and the overall charge of the ion is +1. So, the oxidation state of nitrogen in NH4+ is -3.In the nitrate ion NO3- , the nitrogen atom has an oxidation state of +5. This is because oxygen has an oxidation state of -2, and there are three oxygen atoms, making a total of -6. The overall charge of the ion is -1, so the oxidation state of nitrogen in NO3- is +5.Now let's analyze the given reaction:NH4NO3 -> N2O + 2H2OFirst, we need to find the oxidation states of nitrogen in the products:In N2O, the oxidation state of nitrogen is +1. This is because oxygen has an oxidation state of -2, and there are two nitrogen atoms, making a total of +2. So, the oxidation state of each nitrogen in N2O is +1.In the reaction, the nitrogen in NH4+ goes from an oxidation state of -3 to +1. This is an increase in oxidation state, which means the nitrogen in NH4+ is being oxidized.The nitrogen in NO3- goes from an oxidation state of +5 to +1. This is a decrease in oxidation state, which means the nitrogen in NO3- is being reduced.So, in the given reaction, the nitrogen in NH4+ is being oxidized, and the nitrogen in NO3- is being reduced.