In the compound KMnO4, we have the following atoms: potassium K , manganese Mn , and oxygen O . To determine the oxidation state of each atom, we'll use the general rules for assigning oxidation states.1. Potassium K : As an alkali metal, potassium has an oxidation state of +1.2. Oxygen O : In most compounds, oxygen has an oxidation state of -2. In KMnO4, there are four oxygen atoms, so the total oxidation state for oxygen is -8.3. Manganese Mn : To determine the oxidation state of manganese, we'll use the fact that the sum of the oxidation states of all atoms in a neutral compound is zero. In this case, we have: +1 + Mn oxidation state + -8 = 0Solving for the Mn oxidation state, we get:Mn oxidation state = +7So, the oxidation states of each atom in KMnO4 are:- Potassium K : +1- Manganese Mn : +7- Oxygen O : -2 for each oxygen atom