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What is the volume of 0.2 M hydrochloric acid that will completely react with 25 ml of 0.1 M sodium hydroxide in a neutralization reaction?

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In a neutralization reaction, the moles of acid must equal the moles of base. The reaction between hydrochloric acid  HCl  and sodium hydroxide  NaOH  is as follows:HCl + NaOH  NaCl + H2OTo find the volume of 0.2 M HCl needed to react with 25 mL of 0.1 M NaOH, we can use the formula:moles of acid = moles of baseMolarity  acid   Volume  acid  = Molarity  base   Volume  base Let V be the volume of HCl needed:0.2 M  V = 0.1 M  25 mLV =  0.1 M  25 mL  / 0.2 MV = 12.5 mLSo, 12.5 mL of 0.2 M hydrochloric acid is needed to completely react with 25 mL of 0.1 M sodium hydroxide in a neutralization reaction.

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