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What is the concentration of a hydrochloric acid (HCl) solution if 25.0 ml of it requires 30.0 ml of 0.1 M sodium hydroxide (NaOH) to completely react in a titration?

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ago by (470 points)
To solve this problem, we can use the concept of stoichiometry and the balanced chemical equation for the reaction between hydrochloric acid  HCl  and sodium hydroxide  NaOH :HCl  aq  + NaOH  aq   NaCl  aq  + H2O  l From the balanced equation, we can see that the mole ratio of HCl to NaOH is 1:1.First, we need to find the moles of NaOH used in the reaction:moles of NaOH = volume of NaOH  L   concentration of NaOH  M moles of NaOH = 0.030 L  0.1 Mmoles of NaOH = 0.003 molesSince the mole ratio of HCl to NaOH is 1:1, the moles of HCl in the reaction are also 0.003 moles.Now, we can find the concentration of the HCl solution:concentration of HCl  M  = moles of HCl / volume of HCl  L concentration of HCl  M  = 0.003 moles / 0.025 Lconcentration of HCl  M  = 0.12 MTherefore, the concentration of the hydrochloric acid solution is 0.12 M.
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