To determine the standard enthalpy of formation for methane CH4 , we will use the combustion reactions of methane and hydrogen gas H2 and the given standard enthalpy values.The combustion reactions are as follows:1. CH4 g + 2 O2 g CO2 g + 2 H2O l H1 = -890.3 kJ/mol2. H2 g + 1/2 O2 g H2O l H2 = -285.8 kJ/molWe need to manipulate these equations to isolate the formation of CH4. First, we will multiply equation 2 by 2 to match the amount of H2O in equation 1:2 * H2 g + 1/2 O2 g H2O l 2 * H2 = 2 * -285.8 kJ/mol This gives us:3. 2 H2 g + O2 g 2 H2O l H3 = -571.6 kJ/molNow, we will subtract equation 3 from equation 1 to isolate the formation of CH4: CH4 g + 2 O2 g CO2 g + 2 H2O l - 2 H2 g + O2 g 2 H2O l This results in:4. CH4 g + O2 g - 2 H2 g CO2 g - O2 g Simplifying the equation, we get:5. CH4 g - 2 H2 g CO2 g - O2 g Now, we will subtract the enthalpy values of equations 1 and 3:H4 = H1 - H3 = -890.3 kJ/mol - -571.6 kJ/mol = -318.7 kJ/molSo, the standard enthalpy of formation for methane CH4 is -318.7 kJ/mol.