To calculate the standard enthalpy change for the combustion reaction of methane, we can use the following equation:Hrxn = Hf products - Hf reactants where Hrxn is the standard enthalpy change for the reaction, Hf products is the sum of the standard enthalpies of formation of the products, and Hf reactants is the sum of the standard enthalpies of formation of the reactants.First, we need to find the standard enthalpy of formation for CO2 g . We can use the given Hrxn and the enthalpies of formation for CH4 g and H2O l to do this:-890.4 kJ/mol = [Hf CO2 + 2 Hf H2O ] - [Hf CH4 + 2 Hf O2 ]Since the standard enthalpy of formation for an element in its standard state O2 g in this case is zero, we can simplify the equation:-890.4 kJ/mol = [Hf CO2 + 2 -285.8 kJ/mol ] - -74.8 kJ/mol Now, we can solve for Hf CO2 :Hf CO2 = -890.4 kJ/mol + 74.8 kJ/mol - 2 -285.8 kJ/mol Hf CO2 = -393.5 kJ/molNow that we have the standard enthalpy of formation for CO2 g , we can calculate the standard enthalpy change for the combustion reaction of methane:Hrxn = [Hf CO2 + 2 Hf H2O ] - [Hf CH4 + 2 Hf O2 ]Hrxn = [ -393.5 kJ/mol + 2 -285.8 kJ/mol ] - [ -74.8 kJ/mol + 2 0 kJ/mol ]Hrxn = -965.1 kJ/molTherefore, the standard enthalpy change for the combustion reaction of methane CH4 to produce carbon dioxide CO2 and water H2O at 298 K is -965.1 kJ/mol.