First, we need to determine the number of moles of NaOH in 10 g. The molar mass of NaOH is:NaOH = 22.99 g/mol Na + 15.999 g/mol O + 1.007 g/mol H = 39.996 g/molNow, we can calculate the number of moles of NaOH:moles of NaOH = mass / molar massmoles of NaOH = 10 g / 39.996 g/mol = 0.2501 molNext, we can calculate the standard enthalpy change for the dissolution of 0.2501 mol of NaOH using the given molar enthalpy of dissolution:H = moles molar enthalpy of dissolutionH = 0.2501 mol -44.5 kJ/mol = -11.129 kJThe standard enthalpy change for the dissolution of 10 g of NaOH in 100 mL of water at 25C is -11.129 kJ.