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Calculate the standard enthalpy change for the dissolution of 5.36 g of NaOH in 100.0 mL of water, given that the molar enthalpy of dissolution for NaOH is -44.5 kJ/mol.

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To calculate the standard enthalpy change for the dissolution of NaOH, we first need to determine the number of moles of NaOH being dissolved. 1. Calculate the moles of NaOH:NaOH has a molar mass of 22.99 g/mol  Na  + 15.999 g/mol  O  + 1.007 g/mol  H  = 39.996 g/mol.moles of NaOH = mass / molar massmoles of NaOH = 5.36 g / 39.996 g/mol = 0.134 mol2. Calculate the enthalpy change:Now that we have the moles of NaOH, we can calculate the enthalpy change using the molar enthalpy of dissolution.H = moles  molar enthalpy of dissolutionH = 0.134 mol   -44.5 kJ/mol H = -5.963 kJThe standard enthalpy change for the dissolution of 5.36 g of NaOH in 100.0 mL of water is -5.963 kJ.

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