To calculate the standard enthalpy change of the dissolution reaction, we first need to determine the number of moles of NaOH in 5.00 g.The molar mass of NaOH is:Na = 22.99 g/molO = 16.00 g/molH = 1.01 g/molTotal = 22.99 + 16.00 + 1.01 = 40.00 g/molNow, we can calculate the number of moles of NaOH in 5.00 g:moles = mass / molar massmoles = 5.00 g / 40.00 g/mol = 0.125 molWe are given the molar heat of solution of NaOH as -44.5 kJ/mol. To calculate the standard enthalpy change of the dissolution reaction, we multiply the molar heat of solution by the number of moles of NaOH:H = moles molar heat of solutionH = 0.125 mol -44.5 kJ/mol = -5.56 kJThe standard enthalpy change of the dissolution reaction for 5.00 g of NaOH in 100 mL of water is -5.56 kJ.