Question

What is the concentration of hydrochloric acid (HCl) in a 100 mL solution if it requires 50 mL of 0.1 M sodium hydroxide (NaOH) to neutralize it during a titration process?

Answer 1

To find the concentration of hydrochloric acid  HCl  in the solution, we can use the concept of stoichiometry and the balanced chemical equation for the neutralization reaction between HCl and NaOH:HCl + NaOH  NaCl + H2OFrom the balanced equation, we can see that 1 mole of HCl reacts with 1 mole of NaOH.We are given that 50 mL of 0.1 M NaOH is required to neutralize the HCl solution. First, we need to find the moles of NaOH used in the reaction:moles of NaOH = volume  L   concentration  M moles of NaOH = 0.050 L  0.1 M = 0.005 molesSince the mole ratio of HCl to NaOH is 1:1, the moles of HCl in the 100 mL solution will also be 0.005 moles.Now, we can find the concentration of HCl in the 100 mL solution:concentration  M  = moles of HCl / volume  L concentration  M  = 0.005 moles / 0.100 L = 0.05 MSo, the concentration of hydrochloric acid  HCl  in the 100 mL solution is 0.05 M.