Question

What is the concentration of hydrochloric acid (HCl) in a solution if 25 mL of 0.1 M sodium hydroxide (NaOH) was required to neutralize 50 mL of HCl solution using titration technique?

Answer 1

To solve this problem, we can use the concept of stoichiometry and the balanced chemical equation for the reaction between sodium hydroxide and hydrochloric acid:NaOH + HCl  NaCl + H2OFrom the balanced equation, we can see that the mole ratio between NaOH and HCl is 1:1.First, we need to find the moles of NaOH used in the reaction:moles of NaOH = Molarity  Volumemoles of NaOH = 0.1 M  0.025 L  converting 25 mL to liters moles of NaOH = 0.0025 molesSince the mole ratio between NaOH and HCl is 1:1, the moles of HCl in the 50 mL solution will also be 0.0025 moles.Now we can find the concentration of HCl in the 50 mL solution:Molarity of HCl = moles of HCl / Volume of HCl solutionMolarity of HCl = 0.0025 moles / 0.050 L  converting 50 mL to liters Molarity of HCl = 0.05 MSo, the concentration of hydrochloric acid  HCl  in the solution is 0.05 M.