Question

Calculate the equilibrium constant (Kc) for the following reaction at 300 K:        N2(g) + 3 H2(g) ↔ 2 NH3(g)    given that at equilibrium, the concentration of N2 is 0.12 M, H2 is 0.20 M, and NH3 is 0.16 M.

Answer 1

To calculate the equilibrium constant  Kc  for the given reaction, we can use the formula:Kc = [NH3]^2 /  [N2] * [H2]^3 At equilibrium, the concentrations are given as:[N2] = 0.12 M[H2] = 0.20 M[NH3] = 0.16 MNow, we can plug these values into the formula:Kc =  0.16 ^2 /  0.12 *  0.20 ^3 Kc = 0.0256 /  0.12 * 0.008 Kc = 0.0256 / 0.00096Kc  26.67Therefore, the equilibrium constant  Kc  for the given reaction at 300 K is approximately 26.67.