Question

Sure, here's a problem for you:Consider the following reaction: N2 (g) + 3 H2 (g) ⇌ 2 NH3 (g)If the equilibrium concentrations of N2, H2 and NH3 are 0.25 M, 0.75 M and 0.50 M, respectively, calculate the equilibrium constant (Kc) for the reaction.

Answer 1

To calculate the equilibrium constant  Kc  for the reaction, we can use the expression:Kc = [NH3]^2 /  [N2] * [H2]^3 where the concentrations are given in molarity  M .Given the equilibrium concentrations of N2, H2, and NH3 are 0.25 M, 0.75 M, and 0.50 M, respectively, we can plug these values into the expression:Kc =  0.50 ^2 /  0.25 *  0.75 ^3 Kc = 0.25 /  0.25 * 0.421875 Kc = 0.25 / 0.10546875Kc  2.37So, the equilibrium constant  Kc  for the reaction is approximately 2.37.