Question

Calculate the equilibrium constant (Kc) at 298 K for the reaction: 2 NH3(g) ⇌ N2(g) + 3 H2(g) given that the equilibrium concentration of NH3 is 0.20 M, N2 is 0.025 M, and H2 is 0.060 M.

Answer 1

To calculate the equilibrium constant  Kc  for the reaction, we can use the expression:Kc = [N2] * [H2]^3 / [NH3]^2where [N2], [H2], and [NH3] represent the equilibrium concentrations of N2, H2, and NH3, respectively.Given the equilibrium concentrations:[NH3] = 0.20 M[N2] = 0.025 M[H2] = 0.060 MPlug these values into the Kc expression:Kc =  0.025  *  0.060 ^3 /  0.20 ^2Kc =  0.025  *  0.000216  /  0.04 Kc = 0.000135 / 0.04Kc  3.375  10^-3So, the equilibrium constant  Kc  for the reaction at 298 K is approximately 3.375  10^-3.