Question

Calculate the equilibrium constant (Kc) for the reaction N2(g) + 3H2(g) ⇌ 2NH3(g) if the equilibrium concentration of nitrogen (N2) is 0.025 M, hydrogen (H2) is 0.10 M, and ammonia (NH3) is 0.015 M.

Answer 1

To calculate the equilibrium constant  Kc  for the reaction, we can use the expression:Kc = [NH3]^2 /  [N2] * [H2]^3 Given the equilibrium concentrations:[N2] = 0.025 M[H2] = 0.10 M[NH3] = 0.015 MPlug the values into the Kc expression:Kc =  0.015 ^2 /  0.025 *  0.10 ^3 Kc = 0.000225 /  0.025 * 0.001 Kc = 0.000225 / 0.000025Kc = 9Therefore, the equilibrium constant  Kc  for the reaction is 9.