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Calculate the enthalpy of formation of water (H2O) given the enthalpies of formation of hydrogen gas (H2) and oxygen gas (O2) are -286 kJ/mol and 0 kJ/mol, respectively.

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The enthalpy of formation of water  H2O  can be calculated using the following balanced chemical equation:H2  g  + 1/2 O2  g   H2O  l The enthalpy of formation  Hf  of a compound is the change in enthalpy when 1 mole of the compound is formed from its constituent elements in their standard states. In this case, we are given the enthalpies of formation for hydrogen gas  H2  and oxygen gas  O2 , which are -286 kJ/mol and 0 kJ/mol, respectively.Since the enthalpy of formation of the elements in their standard states is zero, we can use the following equation to calculate the enthalpy of formation of water:Hf  H2O  = Hf  H2  + 1/2 Hf  O2 Hf  H2O  = -286 kJ/mol + 1/2  0 kJ/mol Hf  H2O  = -286 kJ/molTherefore, the enthalpy of formation of water  H2O  is -286 kJ/mol.

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