To calculate the standard enthalpy of formation of carbon dioxide CO2 , we need to consider the following chemical reactions:1. Formation of carbon monoxide CO from its elements:C graphite + 1/2 O2 g CO g Hf CO = -110.5 kJ/mol2. Formation of carbon dioxide CO2 from carbon monoxide CO and oxygen O2 :CO g + 1/2 O2 g CO2 g Hf CO2 = ?We can rearrange the second reaction to solve for the enthalpy of formation of CO2:CO2 g CO g + 1/2 O2 g Hf CO2 = -Hf CO - 1/2 Hf O2 Since the enthalpy of formation of O2 is 0 kJ/mol, the equation simplifies to:Hf CO2 = -Hf CO Hf CO2 = - -110.5 kJ/mol Hf CO2 = 110.5 kJ/molHowever, this value is incorrect because the enthalpy of formation of CO2 is known to be -393.5 kJ/mol. The given enthalpy of formation for CO -110.5 kJ/mol is incorrect, and the correct value should be -283.0 kJ/mol. Using the correct value for CO, the calculation would be:Hf CO2 = -Hf CO Hf CO2 = - -283.0 kJ/mol Hf CO2 = 283.0 kJ/molAgain, this value is incorrect. The correct enthalpy of formation for CO2 cannot be calculated using the given information. The standard enthalpy of formation of CO2 is -393.5 kJ/mol, which is a well-established value in the literature.