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A 25 g sample of water at 25°C is heated by 200 J. The temperature of the water increases to 40°C. Calculate the specific heat capacity of water.

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To calculate the specific heat capacity of water, we can use the formula:q = mcTwhere q is the heat energy  in joules , m is the mass of the substance  in grams , c is the specific heat capacity  in J/gC , and T is the change in temperature  in C .We are given the following information:- Mass of water  m  = 25 g- Initial temperature  T1  = 25C- Final temperature  T2  = 40C- Heat energy  q  = 200 JFirst, we need to find the change in temperature  T :T = T2 - T1 = 40C - 25C = 15CNow, we can rearrange the formula to solve for the specific heat capacity  c :c = q /  mT Plugging in the given values:c = 200 J /  25 g  15C  = 200 J / 375 gC = 0.533 J/gCTherefore, the specific heat capacity of water in this case is approximately 0.533 J/gC. Note that the generally accepted value for the specific heat capacity of water is 4.18 J/gC, so this calculated value is likely affected by experimental error or other factors not accounted for in the problem.

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